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If a line, y = mx + c is a tangent to the circle, (x – 3) 2 + y 2 = 1 and it is perpendicular to a line L 1' where L 1 is the tangent to the circle, x 2 + y 2 = 1 at the point         2 1 , 2 1 ; then :

1. c 2 + 7c + 6 = 0
2. c 2 + 6c + 7 = 0
3. c 2 – 6c + 7 = 0
4. c 2 – 7c + 6 = 0

Correct answer: c 2 + 6c + 7 = 0

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