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If θ 1 and θ 2 be respectively the smallest and the largest values of θ in (0, 2 π ) – { π } which satisfy the equation, 2cot 2 θ – θ sin 5 + 4 = 0, then ∫ θ θ θ 2 1 3 cos 2 d θ is equal to:
- 3 π
- 9 π
- 6 1 3 + π
- 3 2 π
Correct answer: 3 π
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