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If f(a + b + 1 – x) = f(x), for all x, where a and b are fixed positive real numbers, then b a 1 + ∫ + + b a dx )) 1 x ( f ) x ( f ( x is equal to :

1. ∫ + + 1 b 1 a dx ) x ( f
2. ∫ − − 1 b 1 a dx ) x ( f
3. ∫ + + + 1 b 1 a dx ) 1 x ( f
4. ∫ − − + 1 b 1 a dx ) 1 x ( f

Correct answer: ∫ − − + 1 b 1 a dx ) 1 x ( f

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