Exams › JEE Main › General
7 A 10 F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becom es 20 V. The capacitance of the second capacitor is :
- 10 F
- 15 F
- 20 F
- 30 F
Correct answer: 15 F
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →