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If a circle of radius R passes through the origin O and intersects the coordinates axes at A and B, then the locus of the foot of perpendicular from O on AB is :

1. (x 2 + y 2 ) 2 = 4R 2 x 2 y 2
2. (x 2 + y 2 ) (x + y) = R 2 xy
3. (x 2 + y 2 ) 2 = 4Rx 2 y 2
4. (x 2 + y 2 ) 3 = 4R 2 x 2 y 2

Correct answer: (x 2 + y 2 ) 3 = 4R 2 x 2 y 2

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