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If y(x) is the solution of the differential equation dx dy + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + x 1 x 2 y = e –2x , x > 0, where y

1. = 2 1 e –2 , then :
2. y(log e 2) = log e 4
3. y(x) is decreasing in (0, 1)
4. y(log e 2) = 4 2 log e (4) y(x) is decreasing in ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ 1 , 2 1

Correct answer: y(log e 2) = 4 2 log e (4) y(x) is decreasing in ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ 1 , 2 1

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