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An equilateral triangle ABC is cut from a thin solid sheet of wood. (see figure) D, E and F are the mid-points of its sides as shown and G is the centre of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I 0 . If the smaller triangle DEF is removed from ABC, the moment of inertia of the remaining figure about the same axis is I. then : A F D E C B .G
- I = 4 I 0
- I = 0 I 16 15
- I = 0 I 16 9
- I = 0 I 4 3
Correct answer: I = 0 I 16 15
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