Exams › JEE Main › General
A body is projected at t = 0 with a velocity 10 ms –1 at an angle of 60° with the horizontal. The radius of curvature of its trajectory at t = 1s is R. neglecting air resistance and taking acceleration due to gravity g = 10 ms –2 , the value of R is :
- 2.8 m
- 5.1 m
- 2.5 m
- 10.3m
Correct answer: 2.8 m
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →