Exams › JEE Main › General
In a Young's double slit experiment, the path difference, at a certain point on the screen, between two interfering waves is 8 1 th of wavelength. The ratio of the intensity at this point to that at the centre of a bright fringe is close to :
- 0.94
- 0.85
- 0.74
- 0.80
Correct answer: 0.85
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →