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Let O(0, 0) and A(0, 1) be two fixed points. Then the locus of a point P such that the perimeter of Δ AOP is 4, is -
- 8x 2 + 9y 2 – 9y = 18
- 9x 2 + 8y 2 – 8y = 16
- 9x 2 – 8y 2 + 8y = 16
- 8x 2 – 8y 2 + 9y = 18
Correct answer: 9x 2 + 8y 2 – 8y = 16
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