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If ƒ(x) = log e ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + − x 1 x 1 , |x| < 1, then ƒ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + 2 x 1 x 2 is equal to -

1. 2ƒ(x)
2. 2ƒ(x 2 )
3. (ƒ(x)) 2
4. – 2ƒ(x)

Correct answer: 2ƒ(x)

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