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Let y = y(x) be the solution of the differential equation, (x 2 + 1) 2 dx dy + 2x(x 2 + 1)y = 1 such that y(0) = 0. If a y

1. = 32 π , then the value of ‘a’ is -
2. 2 1
3. 4 1
4. 16 1 (4) 1

Correct answer: 4 1

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