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Given that Θ O H / O 2 2 E = + 1.23 V; Θ − − 2 4 2 8 2 SO / O S E = 2.05 V Θ − Br / Br 2 E = + 1.09 V; Θ + Au / Au 3 E = +1.4 V The strongest oxidizing agent is -

1. − 2 8 2 O S
2. O 2
3. Au 3+
4. Br 2

Correct answer: − 2 8 2 O S

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