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Two particles move at right angle to each other. Their de-Broglie wavelengths are λ 1 and λ 2 respectively. The particles suffer perfectly inelastic collision. The de-Broglie wavelength λ , of the final particle, is given by -

1. λ = 2 2 1 λ + λ
2. 2 1 λ = 2 1 1 λ + 2 2 1 λ
3. λ 2 = 1 1 λ + 2 1 λ
4. λ = 2 1 λ λ

Correct answer: 2 1 λ = 2 1 1 λ + 2 2 1 λ

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