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An alternating voltage V(t) = 220 sin 100 π t volt is applied to a purely resistive load of 50 Ω . The time taken for the current to rise from half of the peak value to the peak value is -
- 5 ms
- 7.2 ms
- 3.3 ms
- 2.2 ms
Correct answer: 3.3 ms
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