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The Boolean expression ((p ∧ q) ∨ (p ∨ ~ q)) ∧ (~ p ∧ ~ q) is equivalent to :

1. p ∧ q
2. p ∧ (~ q)
3. p ∨ (~ q)
4. (~ p) ∧ (~ q)

Correct answer: (~ p) ∧ (~ q)

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