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For x > 1, if (2x) 2y = 4e 2x – 2y , then (1 + log e 2x) 2 dx dy is equal to :

1. x 2 log x 2 log x e e −
2. log e 2x
3. x log e 2x
4. x 2 log x 2 log x e e +

Correct answer: x 2 log x 2 log x e e −

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