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Let y = y(x) be the solution of the differential equation, . ) 1 x ( , x log x y dx dy x e > = + If 2y

1. = log e 4 – 1, then y(e) is equal to :
2. 2 e −
3. 2 e 2 −
4. 4 e 2 (4) 4 e

Correct answer: 4 e 2 (4) 4 e

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