Exams › JEE Main › General
In the figure shown, after the switch 'S' is turned from position 'A' to position 'B', the energy dissipated in the circuit in terms of capacitance 'C' and total charge 'Q' is : ε C 3C A B S
- C Q 8 1 2
- C Q 8 5 2
- C Q 4 3 2
- C Q 8 3 2
Correct answer: C Q 8 3 2
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →