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The position vector of the centre of mass → r cm of an asymmetric uniform bar of negligible area of cross- section as shown in figure is : 3L 2L L L

1. → r cm = 8 11 L y ˆ L 8 3 x ˆ +
2. → r cm = 8 5 L y ˆ L 8 13 x ˆ +
3. → r cm = 8 13 L y ˆ L 8 5 x ˆ +
4. → r cm = 8 3 L y ˆ L 8 11 x ˆ +

Correct answer: → r cm = 8 13 L y ˆ L 8 5 x ˆ +

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