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The value of the integral ∫ − 1 0 1 cot x (1–x 2 +x 4 ) dx is :

1. 2 1 4 − π log e 2
2. 2 π – log e 2
3. 4 π – log e 2
4. 2 1 2 − π log e 2

Correct answer: 2 1 4 − π log e 2

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