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The area (in sq. units) of the smaller of the two circles that touch the parabola, y 2 = 4x at the point (1, 2) and the x-axis is :

1. 4 π (2 – 2 )
2. 8 π (3 – 2 2 )
3. 4 π (3 + 2 )
4. 8 π (2 – 2 )

Correct answer: 8 π (3 – 2 2 )

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