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If ( ) ∫ + + dx ) x sec x tan x (sec ) x ( f x tan x sec e 2 x sec = e secx f(x) + C, then a possible choice of f(x) is :

1. secx – tanx – 2 1
2. secx + xtanx – 2 1
3. secx + tanx + 2 1
4. xsecx + tanx + 2 1

Correct answer: secx + tanx + 2 1

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