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Two materials having coefficients of thermal conductivity '3K' and 'K' and thickness d and '3d' respectively, are joined to form a slab as shown in the figure. The temperatures of the outer surfaces are ' θ 2 ' and ' θ 1 ' respectivlely, ( θ 2 > θ 1 ). The temperature at the interface is : θ 2 3K K d 3d θ 1
- 2 1 2 θ + θ
- 3 2 3 2 1 θ + θ
- 10 9 10 2 1 θ + θ
- 6 5 6 2 1 θ + θ CAREER POINT CAREER POINT , CP Tower, IPIA, Road No.1, Kota (Raj.), : 0744-6630500 | www.ecareerpoint.com Email: info@cpil.in Page # 6 JEE Main Online
Correct answer: 10 9 10 2 1 θ + θ
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