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ExamsJEE MainGeneral

The position of a particle as a function of time t, is given by x(t) = at + bt 2 – ct 3 where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be :

  1. a + c 4 b 2
  2. a + c b 2
  3. a + c 3 b 2
  4. a + c 2 b 2

Correct answer: a + c 3 b 2

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