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50 W/m 2 energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1 m 2 surface area will be close to (c = 3×10 8 m/s) :
- 20 × 10 –8 N
- 35 × 10 –8 N
- 10 × 10 –8 N
- 15 × 10 –8 N
Correct answer: 20 × 10 –8 N
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