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ExamsJEE MainGeneral

If the function f defined on ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π π 3 , 6 by f(x) = ⎪ ⎪ ⎩ ⎪ ⎪ ⎨ ⎧ π = π ≠ 4 x , k 4 x 1 – x cot 1 – x cos 2 is continuous, then k is equal to :

  1. 2 1
  2. 1
  3. 2 1
  4. 2

Correct answer: 2 1

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