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If ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 1 1 ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 2 1 ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 3 1 …….. ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 1 – n 1 = ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 78 1 , then the inverse of ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 n 1 is :

1. ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 12 0 1
2. ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 13 2 1
3. ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 12 – 1
4. ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 13 – 1

Correct answer: ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 1 0 13 – 1

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