Exams › JEE Main › General
If a tangent to the circle x 2 + y 2 = 1 intersects the coordinate axes at distinct points P and Q, then the locus of the mid-point of PQ is :
- x 2 + y 2 – 2x 2 y 2 = 0
- x 2 + y 2 – 4x 2 y 2 = 0
- x 2 + y 2 – 16x 2 y 2 = 0
- x 2 + y 2 – 2xy = 0
Correct answer: x 2 + y 2 – 4x 2 y 2 = 0
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →