StreakPeaked· Practice

ExamsJEE MainGeneral

Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2 nd Balmer line (n = 4 to n = 2) will be :

  1. 889.2 nm
  2. 388.9 nm
  3. 488.9 nm
  4. 642.7 nm

Correct answer: 488.9 nm

Related JEE Main General questions

⚔️ Practice JEE Main General free + battle 1v1 →