StreakPeaked· Practice

ExamsJEE MainGeneral

The electric field of light wave is given as → E = 10 –3 cos C N x ˆ t 10 6 2 10 5 x 2 14 7 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ × × π − × π − . This light falls on a metal plate of work function 2eV. The stopping potential of the photo-electrons is : Given, E (in eV) = ) Å in ( 12375 λ .

  1. 0.72 V
  2. 2.0 V
  3. 0.48 V
  4. 2.48 V

Correct answer: 0.48 V

Related JEE Main General questions

⚔️ Practice JEE Main General free + battle 1v1 →