Exams › JEE Main › General
The magnetic field of a plane electromagnetic wave is given by : → B = B 0 i ˆ [cos (kz – ω t)] + B 1 j ˆ cos (kz + ω t) Where B 0 = 3 × 10 –5 T and B 1 = 2 × 10 –6 T. The rms value of the force experienced by a stationary charge Q = 10 –4 C at z = 0 is closest to -
- 0.6 N
- 3 × 10 –2 N
- 0.9 N
- 0. 1N
Correct answer: 0.6 N
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →