Exams › JEE Main › General
A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ , where θ is the angle by which is has rotated, is given as k θ 2 . If its moment of inertia is I then the angular acceleration of the disc is -
- θ I k
- θ I 2 k
- θ I 4 k
- θ I k 2
Correct answer: θ I k 2
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →