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Let f(x) = 5 – |x – 2| and g(x) = |x + 1|, x ∈ R. If f(x) attains minimum value at β , then αβ → – x lim 8 x 6 – x ) 6 x 5 – x )( 1 – x ( 2 2 + + is equal to :

1. 2 1
2. 2 1 –
3. 2 3
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Correct answer: 2 1

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