Exams › JEE Main › General
An electron, moving along the x-axis with an initial energy of 100 eV, enters a region of magnetic field → B = (1.5 × 10 –3 T) k ˆ at S (See figure). The field extends between x = 0 and x = 2 cm. The electron is detected at the point Q on a screen placed 8 cm away from the point S. The distance d between P and Q (on the screen) is : (electron’s charge = 1.6 × 10 –19 C, mass of electron = 9.1 × 10 –31 kg) P d S 8 cm 2 cm Q
- 2.25 cm
- 12.87 cm
- 1.22 cm
- 11.65 cm
Correct answer: 12.87 cm
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →