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Consider the differential equation, y 2 dx + ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ − y 1 x dy = 0, If value of y is 1 when x = 1, then the value of x for which y = 2, is :

1. e 1 2 3 −
2. e 2 3 −
3. e 1 2 1 +
4. e 1 2 5 +

Correct answer: e 1 2 3 −

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