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When M 1 gram of ice at –10°C (specific heat = 0.5 cal g –1 ºC –1 ) is added to M 2 , gram of water at 50°C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g –1 is :

1. 5 M M 50 1 2 −
2. 1 2 M M 50
3. 5 M M 5 1 2 −
4. 50 M M 5 2 1 −

Correct answer: 5 M M 50 1 2 −

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