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A galvanometer of resistance 100 Ω has 50 divisions on its scale and has sensitivitv of 20 μ A/division. It is to be converted to a voltmeter with three ranges of 0-2V, 0-10 V and 0-20 V. The appropriate circuit to do so is

1. R 1 R 2 R 3 G 2V 10V 20V R 1 = 1900 Ω R 2 = 8000 Ω R 3 = 10000 Ω
2. R 1 R 2 R 3 G 20V 10V 2V R 1 = 19900 Ω R 2 = 9900 Ω R 3 = 1900 Ω
3. R 1 R 2 R 3 G 2V 10V 20V R 1 = 1900 Ω R 2 = 9900 Ω R 3 = 19900 Ω
4. R 1 R 2 R 3 G 2V 10V 20V R 1 = 2000 Ω R 2 = 8000 Ω R 3 = 10000 Ω

Correct answer: R 1 R 2 R 3 G 2V 10V 20V R 1 = 1900 Ω R 2 = 8000 Ω R 3 = 10000 Ω

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