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The trajectory of a projectile near the surface of the earth is given as y = 2x – 9x 2 . If it were launched at an angle θ 0 with speed v 0 then (g = 10 ms –2 ) :
- θ 0 = cos –1 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ 5 1 and v 0 = 3 5 ms –1
- θ 0 = cos –1 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ 5 2 and v 0 = 5 3 ms –1
- θ 0 = sin –1 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ 5 2 and v 0 = 5 3 ms –1
- θ 0 = sin –1 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ 5 1 and v 0 = 3 5 ms –1
Correct answer: θ 0 = cos –1 ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ 5 1 and v 0 = 3 5 ms –1
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