Exams › JEE Main › General
A thin ring of 10 cm radius carries a uniformly distributed charge. The ring rotates at a constant angular speed of 40 π rad s –1 about its axis, perpendicular to its plane. If the magnetic field at its centre is 3.8 × 10 –9 T, then the charge carried by the ring is close to ( μ 0 = 4 π × 10 –7 N/A 2 ).
- 7 × 10 –6 C
- 4 × 10 –5 C
- 2 × 10 –6 C
- 3 × 10 –5 C
Correct answer: 3 × 10 –5 C
Related JEE Main General questions
⚔️ Practice JEE Main General free + battle 1v1 →