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If the tangent to the curve y = 3 x x 2 − , x ∈ ρ, ( x ≠ ± 3 ) , at a point ( α, β ) ≠ (0, 0) on it is parallel to the line 2x + 6y – 11 = 0, then :
- 9 | 2 6 | = β + α
- 11 | 6 2 | = β + α
- 19 | 6 2 | = β + α
- 19 | 2 6 | = β + α
Correct answer: 19 | 2 6 | = β + α
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