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Let y = y(x) be the solution of the differential equation, dx dy + y tan x = 2x + x 2 tan x, x ∈ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π π − 2 , 2 , such that y(0) = 1. Then :

1. 2 4 y 4 y = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π − − ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π
2. 2 4 ' y 4 ' y − π = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π − − ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π
3. 2 2 4 y 4 y 2 + π = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π − + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π
4. 2 4 ' y 4 ' y − = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π − + ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π CAREER POINT CAREER POINT , CP Tower, IPIA, Road No.1, Kota (Raj.), : 0744-6630500 | www.ecareerpoint.com Email: info@cpil.in Page # 9 JEE Main Online

Correct answer: 2 4 ' y 4 ' y − π = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π − − ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π

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