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Let f(x) = log e (sin x), (0 < x < π ) and g(x) = sin –1 (e –x ), (x ≥ 0). If α is a positive real number such that a = (fog)' ( α ) and b = (fog) ( α ), then :
- a α 2 + b α – a = – 2 α 2
- a α 2 + b α + a = 0
- a α 2 – b α – a = 0
- a α 2 + b α – a = 1
Correct answer: a α 2 + b α – a = 1
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