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Two blocks A and B of masses m A = 1 kg and m B = 3 kg are kept on the table as shown in figure. the coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is : [Take g = 10 m/s 2 ] A B F
- 8 N
- 40 N
- 16 N
- 12 N
Correct answer: 16 N
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