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In a Young's double slit experiment, the ratio of the slit's width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be :
- 25 : 9
- 4 : 1
- ( 3 + 1) 4 : 16
- 9 : 1
Correct answer: 9 : 1
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