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A submarine experiences a pressure of 5.05 × 10 6 Pa at a depth of d 1 in a sea. When it goes further to a depth of d 2 , it experiences a pressure of 8.08 × 10 6 Pa. Then d 2 –d 1 is approximately (density of water = 10 3 kg/m 3 and acceleration due to gravity = 10 ms –2 ) :
- 600 m
- 400 m
- 300 m
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Correct answer: 300 m
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