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If Δ 1 = x 1 cos 1 x – sin – cos sin x θ θ θ θ and Δ 2 = x 1 2 cos 1 x – 2 sin – 2 cos 2 sin x θ θ θ θ , x ≠ 0 ; then for all θ ∈ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ π 2 , 0 :

1. Δ 1 – Δ 2 = x (cos 2 θ – cos 4 θ )
2. Δ 1 + Δ 2 = – 2x 3
3. Δ 1 + Δ 2 = – 2(x 3 + x –1)
4. Δ 1 – Δ 2 = – 2x 3

Correct answer: Δ 1 + Δ 2 = – 2x 3

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