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A particle of mass m is moving along a trajectory given by x = x 0 + a cos ω 1 t y = y 0 + b sin ω 2 t The torque, acting on the particle about the origin , at t = 0 is :

1. – m (x 0 2 2 b ω – y 0 2 1 a ω ) k ˆ
2. Zero
3. k ˆ a my 2 1 0 ω +
4. k ˆ ) a y b x (– m 2 1 0 0 ω +

Correct answer: k ˆ a my 2 1 0 ω +

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