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A thin disc of mass M and radius R has mass per unit area σ (r) = kr 2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is :
- 3 MR 2 2
- 6 MR 2
- 3 MR 2
- 2 MR 2
Correct answer: 3 MR 2 2
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