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If the eccentricity of the standard hyperbola passing through the point (4, 6) is 2, then the equation of the tangent to the hyperbola at (4, 6) is -

1. 2x – y – 2 = 0
2. 3x – 2y = 0
3. 2x – 3y + 10 = 0
4. x – 2y + 8 = 0

Correct answer: 2x – y – 2 = 0

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